little problem in my code...can you detect it?

[gigi85]

i have made this little code to detect in a string (min 3 char) if there are special characters....in case they are present my output needs to be F, if there aren't T.

but it doesn't work....

why?

[GerdW]

Hi gigi,

when you ask for help on debugging your code you should attach the actual code, nut just a picture of it!

Meanwhile I had to re-code your picture, but it seems to work for me:

(The size check is up to you...)

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but it doesn't work....

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Has no one told you by now that "doesn't work" isn't a good error description?

What error(s)? What's wrong? Where's your problem at debugging it?

[Amy2312]

There should be "OR" operator insted of "AND" operator. I guess.. 😉

[pincpanter]

Your code seems correct to me... Please upload a small vi so we can test it without actually coding.

GerdW: gigi is working with LV 7.1 so the conditional terminal in the loop is not available.

[MangeshD]

Check this code.

[GerdW]

Hi Paolo,

now you mention it I also remember I gave gigi the advice to use a signature noting that old LabVIEW version...

@gigi:

Use an "AND Array Elements" instead the conditional break of the FOR loop...

[gigi85]

here my code...

signature with labview version done 🙂

after lunch i'll try and array elements (if i'll find it)

[pincpanter]

I overlooked that you need a True getting out the while loop if the string is OK.

Replace <0 with >=0 and change the conditional terminal to "Stop if True".

You may also improve the code replacing the constant 12 with the character array size; this prevents to break the code if you later want to add or remove forbidden characters.

[GerdW]

Hi gigi,

all you need is some boolean logic:

(String constants set to "\-Code" display mode.)

[gigi85]

DONE 🙂

THANK YOU ALL 🙂