02-23-2010 08:12 PM
Solved! Go to Solution.
02-24-2010 12:01 PM
02-24-2010 09:08 PM
02-24-2010 11:58 PM
Hi,
You can do the following:
Circuit connection:
Analog out -> precision shunt resistor (1ohm) -> resistor of interest -> analog out's gnd
You will then put a analog in accross the shunt resistor and another analog in across your resistor of interest.
From the voltage across the shunt and the known resistance (1ohm), you can calculate the current across the resistor of interest (circuit in series). With the calculated current and the voltage measured across the resistor of interest, you can calculate resistance with ohm's law.
Watch out for the following:
1. Since there is a max current rating on your analog out, you can't measure resistance with low value. If low resistance measurement is desired, you can subsitute the analog out with a power supply.
2. Make sure the shunt resistor is rated high enough in power for your application, or it will be fried.
See link below for more info.
http://www.allaboutcircuits.com/vol_1/chpt_8/9.html
02-28-2010 09:42 AM
03-01-2010 12:17 AM
Not really clear about what you want. Can you draw a picture?
Yik
03-01-2010 08:50 PM
I have to develop a tool to get these following functions:
- Use the device as voltímeter;
- Use the device as ammeter;
- (VI) read the current and a file note;
- (VI) read voltage and write a file;
- Divide the values of voltage by the current to find the resistance;
- Build graph of resistance versus time and current;
- I wonder if you can do this with device USB 6009.
Tanks
03-01-2010 08:53 PM
03-01-2010 09:10 PM - edited 03-01-2010 09:11 PM
03-01-2010 10:19 PM