Compound Arithmentic Vs Boolean Or

[SercoSteveB]

What are the values of Numeric Value 1 and Numeric Value 2 following execution of the VI?

NOTE:  Answers are in Hexadecimal

a) Numeric Value 1 = 0x00, Numeric Value 2 = 0x00

b) Numeric Value 1 = 0xAB, Numeric Value 2 = 0x00

c) Numeric Value 1 = 0x00, Numeric Value 2 = 0xAB

d) Numeric Value 1 = 0xAB, Numeric Value 2 = 0xAB

[LordNobady]

D

[Musale]

Answer D

[RAMESHB]

Answer is D.

    you put insted of A0 A and 0B B now you got 11 both out same.

[crossrulz]

D

First of all, you should know that an OR is an OR.  So you should be down to A or D just because both indicators will have the same result.

[LordNobady]

my problem is that I am used to differed boolean icons from my electronics study. I know how an or works.

[crossrulz]

LordNobady wrote:

                       

my problem is that I am used to differed boolean icons from my electronics study. I know how an or works.

                   

Yeah, I can never remember which of those "carrots" is the AND and which is the OR.  Luckily the normal functions look more like the OR and AND gates I learned in college.

[2verb]

D

[SercoSteveB]

I remember it by comparing the symbol on the function against the letter 'A' if the symbol matches the shape of A it is an AND otherwise its an OR.

[MrStevenUND]

D.

[mini09]

Same as well ....

SercoSteveB wrote:

                       

I remember it by comparing the symbol on the function against the letter 'A' if the symbol matches the shape of A it is an AND otherwise its an OR.

                   

[mini09]

Answer D ....

[SercoSteveB]

Answer: D.  Nice one LordNobady, Musale, RAMESHB, crossrulz, 2verb, MrStevenUND & gnshmrthy.

So clearly a bitwise operation, is it possible to do a logical operation on numerical values in LabVIEW,  or would you have to convert to a Bool before the operation

[Balze]

I know it's an old thread, but would like to share my "Eselsbrücke"

(In germany a memory hook is called "Eselsbrücke" which means donkey bridge)

If you place an open triangle on its corner (like in the OR operation), it will fall to one side OR the other.

If you place an open triangle on the open side(like in the AND operation), it will rest on one side AND the other.