03-30-2023 01:42 PM
I want a PWM square wave and I tried these two methods/circuits in the picture attached.
I don't know which of the two is right, but what I don't understand is V(rms) calculated by the voltage probe.
The square wave has a Vpeak = 9V and a Duty Cycle of 35% .. so if I'm not mistaken Vrms = 0.35*9 = 3.15V.
Did I make a mistake when creating the PWM circuit?
If one of them is correct (which one?) ... how do I display Vrms?
Thanks!
Solved! Go to Solution.
03-30-2023 02:29 PM - edited 03-30-2023 03:04 PM
Привет! Пробник долго считает, подождите, и он должен выйти на правильный результат...
Вот подтверждение
03-31-2023 11:57 AM
In the photo you attached, V(rms) is 5.32V (as in my photo attached in the first post) ... but 5.32V is not the Vrms of 9V.
As I wrote: the square wave has a Vpeak = 9V and a Duty Cycle of 35% .. so if I'm not mistaken Vrms = 0.35*9 = 3.15V.
Am I wrong?
In simulation V(rms)=3.15V does not appear (I simulated for 30 seconds)
I noticed, however, that the correct V(rms) value appears in the "yellow box" of the voltage probe during the simulation with the entry V(dc).
03-31-2023 12:37 PM - edited 03-31-2023 12:46 PM
-вы просто путаете понятия постоянную составляющую и действующее напряжение.
Сами посчитаете, или помочь?
03-31-2023 12:58 PM
I noticed now that I miscalculated the RMS value. Thank you for your reply!
@tipa
03-31-2023 01:34 PM