Custom stylesheet, how to retrieve parts of seq file path

[pstestek]

We are building a custom stylesheet for our specific needs that is based on the TR5_Horizontal stylesheet. The location that our sequence files are stored in have particular meaning (ex. part, rev, etc.) and I would like to extract those items to be displayed on the test report instead of the complete path to the sequence file.

I'm not really versed in XPath / XSLT so I've not gotten to far. I have tried some function that should help (like tokenize) however, it seems that I am limited to XSL 1.0.

I have found that I can get the path from the name attribute here: 

<xsl:when test="contains(@name,'#')">
<span style="margin-left:20px;font-size:70%;font-weight:bold;">
(<xsl:value-of select="substring-before(@name, '#')"/>)

If I want to split the path (ex. C:\..\..\..\part\rev\<testname>.seq) into the desired parts, how would I do this? 

[pstestek · Accepted solution]

I was able to resolve my issue with the help of someone outside of this forum. The solution was to create a named template to parse the file path string:

 <xsl:template name="parse-path">

    <xsl:param name="text"/>

    <xsl:variable name="n" select="string-length(translate($text, translate($text, '\', ''), ''))"/>

    <xsl:if test="$n=2">

        <part>

         Part: 

            <i><xsl:value-of select="substring-before($text, '\')"/>|</i>

        </part>

    </xsl:if>

    <xsl:if test="$n=1">

        <rev>

         Rev: 

            <i><xsl:value-of select="substring-before($text, '\')"/>|</i>

        </rev>

    </xsl:if>

    <xsl:if test="$n=0">

        <testname>

         TestName: 

            <i><xsl:value-of select="substring-before($text, '.')"/></i>

        </testname>

    </xsl:if>

    

    <xsl:if test="$n">

        <!-- recursive call -->

        <xsl:call-template name="parse-path">

            <xsl:with-param name="text" select="substring-after($text, '\')"/>

        </xsl:call-template>

    </xsl:if>

 </xsl:template>